Regular expression for multiple occurances in python

Question

I need to parse lines having multiple language codes as below

008800002     Bruxelles-Nord$Br�ussel Nord$<deu>$Brussel Noord$<nld>

• 008800002 being a id
• Bruxelles-Nord$Br ussel Nord$ being name1
• deu being language one
• $Brussel Noord$ being name two
• nld being language two.

SO, the idea is name and language can appear N number of times. I need to collect them all. the language in <> is 3 characters in length (fixed) and all names end with $ sign.

I tried this one but it is not giving expected output.

x = re.compile('(?P<stop_id>\d{9})\s(?P<authority>[[\x00-\x7F]{3}|\s{3}])\s(?P<stop_name>.*)
    (?P<lang_code>(?:[<]\S{0,4}))',flags=re.UNICODE)

I have no idea how to get repeated elements. It takes

Bruxelles-Nord$Br ussel Nord$<deu>$Brussel Noord$ as stop_name and <nld> as language.

Answer 1

Do it in two steps. First separate ID from name/language pairs; then use re.finditer on the name/language section to iterate over the pairs and stuff them into a dict.

import re

line = u"008800002     Bruxelles-Nord$Br�ussel Nord$<deu>$Brussel Noord$<nld>"
m = re.search("(\d+)\s+(.*)", line, re.UNICODE)
id = m.group(1)
names = {}
for m in re.finditer("(.*?)<(.*?)>", m.group(2), re.UNICODE):
    names[m.group(2)] = m.group(1)
print id, names

Answer 2

\b(\d+)\b\s*|(.*?)(?=<)<(.*?)>

Try this.Just grab the captures.see demo.

http://regex101.com/r/hS3dT7/4