I'm working with an array that gives me all the info if print_r but it also says that it is an unidentified index. Code:
foreach ($_SESSION['passo4'] as $key => $value) {
$x = $data_ref[0]['tipo_refeicao']; //gives me the error
echo $x; //echoes 1
print_r($data_ref);
if($key != 'preco'){
//Obter info do tipo de vestuário
$f_r = $dbh->prepare("SELECT tipo_refeicao, preco_acompanhante, preco_participante FROM refeicao WHERE id_extra = '$key'");
$f_r->execute();
$data_ref = $f_r->fetchAll();
echo "<tr><td>".
datasearch($data_tref, 'tipo_refeicao', $x, 'descricao')
."</td>";
echo "<td>". $value ."</td>";
echo "<td>". $data_ext[0]['preco'] * $value ."€</td></tr>";
}
}
Notice
Notice: Undefined offset: 0 in C:\xampp\htdocs\Rot.Aventura\eventos\passo5.php on line 96
Print_r($data_ref):
Array ( [0] => Array ( [id_refeicao] => 4 [id_evento] => 11 [tipo_refeicao] => 1 [preco_participante] => 5 [preco_acompanhante] => 6 [limite_pessoa] => 2 ) )
die($x): 1
Should i hide this notice with @ or is there any way to solve this? (Sorry for the portuguese words)
Since you are in a foreach loop you don't have to use index 0
. foreach
auto increment the index, so on next index 0
is undefined
Please try without index or put $x out of loop
foreach ($_SESSION['passo4'] as $key => $value) {
...
$data_ref = $f_r->fetchAll();
$x = $data_ref['tipo_refeicao']; //gives me the error
or
foreach ($_SESSION['passo4'] as $key => $value) {
...
$x = $data_ref['tipo_refeicao']; //gives me the error
Give it a try
The problem was an error with my code:
$f_r = $dbh->prepare("SELECT tipo_refeicao, preco_acompanhante, preco_participante FROM refeicao WHERE id_extra = '$key'");
Where is id_extra it should be id_refeicao. Thank you for your time and help
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