Overloading operator = error

Question

Im trying to create a stack but im receiving errors with overloading my = operator. The stack is of type template. Heres the code

template <typename T>
T& ::stack& operator =(const stack& other)
{
    if (this == &other) return *this;

    copy(other.stack1[0], other.stack1[other.size], stack1[0]);
    return *this;
}

Any help will be appreciated. Thanks

Answer 1

Please try the below signature

template <typename T>
stack<T>& stack<T>:: operator =(const stack<T>& other)

Answer 2

Try:

template <typename T>
stack<T>& stack<T>::operator =(const stack& other)
{
    if (this == &other) return *this;

    copy(other.stack1[0], other.stack1[other.size], stack1[0]);
    return *this;
}

Answer 3

Apart from incorrect declaration of the operator it seems that there is also incorrect usage of standard algorithm copy within the body of the operator provided that stack1 is an array

I can only suppose that the operator should look as

template <typename T>
stack<T> & stack<T>::operator =( const stack<T> &other )
{
    if ( this == &other ) return *this;

    this->size = other.size; 
    copy( other.stack1, other.stack1 + other.size, this->stack1 );

    return *this;
}