How do I extract the second to last occurrence of a string in MySQL?

Question

I'm using MySQL 5.5.37. I have a TEXT column that contains values resembling ...

... "id":"51b21a0710340adf6501db67"}},"created":"2014-08-22T15:42:57.969Z","id":"53f76502f82c7abf3d01fba5"},"uri":"/v1.1/events/53f76502f82c7abf3d01fba5"}

What I'm trying to figure out is how to extract the 32-character value immediately after the second to last '"id":' string (without the quotes surrounding the 32 character item). What is the easiest way to do this in MySQL?

Answer 1

You can use SUBSTRING_INDEX to find the second to last occurrence, and use LEFT to cut out the first 32 characters that follow (although I suspect you only want 24);

SELECT LEFT(SUBSTRING_INDEX(value, '"id":"', -2), 32) FROM bop

An SQLfiddle to test with .