I'm playing with variadic templates and i'm stuck with the following:
template <class T1, class T2>
auto sum(T1 a, T2 b) ->decltype(a + b){
return a + b;
}
template <class T1, class T2, class... T3>
auto sum(T1 a, T2 b, T3... tail) ->decltype(a + b){
return a + sum(b, tail...);
}
Function calls:
cout << sum(1, 2, 3, 4) << endl; // 10 - OK
cout << sum(1.5, 2, 3, 4) << endl; // 10.5 - OK
cout << sum(1, 2, 3.5, 4) << endl; // 10 !! wrong result
What am I doing wrong here?
sum(1, 2, 3.5, 4)
The first two arguments are of type int
. Therefore in the trailing return type, decltype(a + b)
is int
, so the result is converted to int
- and truncated.
Use std::common_type
:
template <class T1, class T2, class... T3>
typename std::common_type<T1, T2, T3...>::type
sum(T1 a, T2 b, T3... tail)
{
return a + sum(b, tail...);
}
Note that
template <class T1, class T2, class... T3>
auto sum(T1 a, T2 b, T3... tail) ->decltype(a + sum(b, tail...))
Does not work as this second template isn't known in the trailing-return-type, only the first one. With C++14, return type deduction is possible though:
template <class T1, class T2, class... T3>
auto sum(T1 a, T2 b, T3... tail)
{
return a + sum(b, tail...);
}
namespace details{
template<template<class,class>class binary_result, class T, class...Ts>
struct nary_result{using type=T};
template<template<class,class>class binary_result, class T0, class T1, class...Ts>
struct nary_result<binary_result, T0,T1,Ts...>:
nary_result<binary_result,binary_result<T0,T1>,Ts...>
{};
}
template<template<class,class>class binary_result, class...Ts>
using nary_result=typename details::nary_result<binary_result,Ts...>::type;
template<class Lhs, class Rhs>
using binary_sum_result = decltype(std::declval<Lhs>()+std::declval<Rhs>());
template<class...Ts>
using sum_result=nary_result<binary_sum_result,Ts...>;
should do the trick.
Maybe add a decay.
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