How to use Java User Input Scanner with multiple loops

Question

I am trying to create a program that prompts the user to enter a name (1 of three options x,y,or z) and a certain variable (that is less than 10). If both of these inputs are true it will print out the name and the number as : (" you choose x times 2")

I am stuck because I'm new to the java scanner class (and java) and don't know how to configure the code with if statements checking two factors.

Help?

My code so far: I know a lot of it wrong:

import java.util.Scanner;

public class ScannerAndKeyboard {

public static void main(String[] args)
{   Scanner s = new Scanner(System.in);
    System.out.print("Welcome");
    System.out.print( "Enter your name: "  );
    String name = s.nextLine();
    System.out.println( "Hello " + name + "!" );
    System.out.print("Please Enter letter and number: " ); 

    if(s.nextLine().equals(X) && s.nextInt() <= 10)
      System.out.println( "You choose x10");
}
}

Answer 1

This should work for you:

import java.util.Scanner;

public class ScannerAndKeyboard {
    public static void main(String[] args)
    {
        Scanner s = new Scanner(System.in);
        System.out.print("Welcome");
        System.out.print( "Enter your name: "  );
        String name = s.nextLine();
        System.out.println( "Hello " + name + "!" );
        System.out.print("Please Enter letter and number: " ); 
        String X = s.useDelimiter("\\s").next();
        int num = s.nextInt();

        if((X.equalsIgnoreCase("x") || X.equalsIgnoreCase("y") ||
                X.equalsIgnoreCase("z")) && num < 10)
          System.out.println( "You choose "+X+num);
    }
}

I tested by verifying the following inputs (you can modify the prompts):

WelcomeEnter your name: Alvin
Hello Alvin!
Please Enter letter and number: X 9
You choose X9

Answer 2

From your code, I don't see a variable named X . So I'm assuming you want a character comparison.

if(s.nextLine().equals("X") && s.nextInt() <= 10)

Wrap X with double quotes and it should solve your problem.

EDIT:

If you need to add a variable and check for x,y or z then do the following:

import java.util.Scanner;

public class ScannerAndKeyboard {

public static void main(String[] args)
{   Scanner s = new Scanner(System.in);
    System.out.print("Welcome");
    System.out.print( "Enter your name: "  );
    String name = s.nextLine();
    System.out.println( "Hello " + name + "!" );
    System.out.print("Please Enter letter and number: " ); 
    String X = s.nextLine();
    if((X.equalsIgnoreCase("x") || X.equalsIgnoreCase("y") || X.equalsIgnoreCase("z")) && s.nextInt() <= 10)
      System.out.println( "You choose "+X+" 10");
}
}

EDIT 2

If they are to be in the same line, then do this:

import java.util.Scanner;

public class ScannerAndKeyboard {

public static void main(String[] args)
{   Scanner s = new Scanner(System.in);
    System.out.print("Welcome");
    System.out.print( "Enter your name: "  );
    String name = s.nextLine();
    System.out.println( "Hello " + name + "!" );
    boolean stat = true;
    while(boolean)
    System.out.print("Please Enter letter and number: " ); 
    String X = s.nextLine();
    String[] X1 = X.split(" ");
    if((X1[0].equalsIgnoreCase("x") || X1[0].equalsIgnoreCase("y") || X1[0].equalsIgnoreCase("z")) && Integer.parseInt(X1[1]) <= 10)
      System.out.println( "You choose "+X1[0]+" "+X1[1]);
      stat = false;
}
else {
    System.out.println("Invalid Input!");
}
}