How to find number of a certain character from file in C?

Question

I'm trying to find out the number of times a letter (say, the letter "b") occurs in paragraph from a file. I'm trying to use arrays to count them, but I'm not sure about how to use the if-else statements properly.

So far all I can do is:

 int main(void)
{
    FILE *fin = fopen("paragraph.txt", "r");
    FILE *fout = fopen("number_of_times_bandc_occurs.txt", "w");
    char line[]='\0';
    int b=0; int c=0;

    while(fscanf("%d", &line) != EOF)
    {
        //Using the if-else statements here is where I'm having difficulty.
    }

    fclose(fout);
    fclose(fin);
    return 0;
}

Btw, I'm kind of a beginner...so I might need some extra explaining. I should also mention that the paragraph has multiple lines of text.

Answer 1

EDIT: I misread you question. To count a specific character you should do something like this:

int ch, countB = 0, countC = 0;
while((ch = fgetc(fp)) != EOF) {
   if(ch == 'B')
      countB++;
   if(ch == 'C')
      countC++;
}

Answer 2

Use

int count=0;
while ((ch = fgetc(fp)) != EOF) 
{
    if (ch == 'b')
    {
        count++;
    }
}
//Then print count

Or

char line[256];
int count=0, i;
char *p;
size_t length;
while(fgets(line, 256, fin))
{
    if ((p=strchr(line, '\n')) != NULL)
        *p = '\0';
    length = strlen(line); //For using strlen() include <string.h>
    for(i=0; i < length; i++)
    {
        if(line[i] == 'b')
            count++;
    }   
}
//Then print count

Answer 3

you can use this simple code patch

long ch_occ[26] = {0};
char ch;
while((ch = fgetc(fp)) != EOF) {
   if(ch == 'a')
      ++ch_occ[0];
else if(ch == 'b')
      ++ch_occ[1];
else if(ch == 'c')
      ++ch_occ[2];
.
.

//Similarly you can create for all 26 alphabets;
//then the first index of array ch_occ will have occurrences of 'a' and next index will have of 'b' and so on...

}