PHP: Regex: Match if doesnt contain

Question

I have two urls (below). I need to match the one that doesn't contain the "story" part in the it. I know i need to use negative lookhead/behind, but i cant for the life of me get it to work

Urls

news/tech/story/2014/oct/28/apple-iphone/261736

news/tech/2014/oct/28/apple-iphone/261736

Current Regex

news\/([a-z0-9-\/]{1,255})(\d{4})\/(\w{3})\/(\d{2})\/([a-z0-9\-]{1,50})\/(\d{1,10})

Example:

http://regex101.com/r/jC7jC4/1

Answer 1

You can use negative lookahead like this:

(?!.*\bstory\b)news\/([a-z0-9-\/]{1,255})(\d{4})\/(\w{3})\/(\d{2})\/([a-z0-9\-]{1,50})\/(\d{1,10})

RegEx Demo

(?!.*\\bstory\\b) is negative lookahead that will stop match if there is a word story in the URL.

Answer 2

你可以尝试这个：

news\/(([a-z0-9-\/](?!story)){1,255})(\d{4})\/(\w{3})\/(\d{2})\/([a-z0-9\-]{1,50})\/(\d{1,10})

Answer 3

如果您不必使用正则表达式，可以使用strpos（）进行检查

 if (strpos($url, 'story') === false