Possible to get the file-path of the class that called a method in Java?

Question

Let's say for instance I have this scenario

C:\\Users\\Name\\Documents\\Workspace\\Project\\Src\\Com\\Name\\Foo.java

Public class Foo {

    public Foo() {
        Bar b = new Bar();
        b.method();
    }
}

Then lets say that class Bar is in a .JAR file that's being used as a library, is it possible to figure out where the class that called method() was from? (in this case, the Foo class)

I've done a little looking around Google and can't find anything, and this code would definately simplify my library quite a bit.

Answer 1

If you need to get path of the caller class file from inside the method Bar#method then you can use something like this:

StackTraceElement[] stackTrace = new Throwable().getStackTrace();
String callerFilePath = getClass().getClassLoader().getResource(stackTrace[1].getClassName().replace('.', '/') + ".class"));

Answer 2

Yes, you can get the path from where the file is being executed. For example, you have the file : C:\\Users\\Name\\Documents\\Workspace\\Project\\Src\\Com\\Name\\Foo.java

After compiling, it will change to : C:\\Users\\Name\\Documents\\Workspace\\Project\\Src\\Com\\Name\\Foo.class

You can use this to get the directory of the file:

System.getProperty("user.dir");

and then you can add this String to it:

String cPath = System.getProperty("user.dir")+"\\Foo.class";

Thus, cPath would be the complete path to the file.

Answer 3

You can use Foo.class.getResource("Foo.class") to get the location of the compiled class file. The question is, how will this help you simplify your library?