sorry for asking on this topic again, but I havent been able to derive a solution to my problem from existing answers.
I have one Table (" Data
") from which I need to pull three columns ( " PID
", " Manager
", " Customer
" ) and only the " PID
" has to be distinct. I dont care which records are pulled for the other columns (" Manger
" / " Customer
" ) it could be the first entry or whatever.
SELECT Distinct PID, Manager, Customer
FROM Data;
Will give me all the rows where PID,Manager and Customer are distinct, so if there is two entrys with the same PID but with a different Manager, I will get two records instead of one.
Thank you very much.
You can do this Hope you will find this helpful
SELECT PID, max(Manager), max(Customer)
FROM Data
group by PID
Or
SELECT PID, min(Manager), min(Customer)
FROM Data
group by PID
EDIT
I will give you an example to explain you the Max & Min Func
Here is the Sample Table
CREATE TABLE data(
PID int ,
Manager varchar(20) ,
Customer varchar(20)
) ;
insert into data
values
(1,'a','b'),
(1,'c','d'),
(3,'1','e'),
(3,'5','e'),
(3,'3','e')
Now,
These are the Three Queries that will return respective outputs,,
select * from data;
SELECT PID, max(Manager), max(Customer)
FROM Data
group by PID;
SELECT PID, min(Manager), min(Customer)
FROM Data
group by PID
Output for the above queries is
Explanation : MAX :
MAX
is returning C & 5
for Manager Coz, C
is greater then A
& likewise 5
is greater then 1 & 3
Min fuction is totally opposite of MAX function & is self explenatory.
I have also created on demo Please click to see the demo on Fiddle
SELECT "PID", max("Manager"), max("Customer")
FROM "Data"
GROUP BY "PID";
This query returns unique "PID"s and max values of "Manager" and "Customer" for each "PID".
DISTINCT is applied for all the columns from the select list. So you need to use GROUP BY + an aggregate function (returns one value for several rows).
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