C *char pointer to char array

Question

I have a *char pointer and a char array. How can I put the value of the pointer in the char array? I've tried

uint8_t i;
char a[10];
char *b = "abcdefghi";
for(i = 0; i < 9; i++)
{
    a[i] = b[i];
}
printf("%s", a);

But this doesn't work.

Answer 1

The size of a is 10 , so is the length of b (including the null terminator). Change

for(i = 0; i < 9; i++)

to

for(i = 0; i < 10; i++)

Answer 2

What you are doing is right.

Juts change i<10 in your for loop.

There are 10 elements in your char array and the array index is from 0-9 .

Answer 3

yet another variant:

#include <stdio.h>
int main(void)
{
    char a[10];
    char *c = a;
    char *b = "abcdefghi";
    for(; *c = *b; ++c, ++b);
    printf("%s", a);
    return 0;
}   

but strcpy() will work faster in any case, since it is often written in assembly language for a specific architecture