Weird Result of String

Question

just curious about it . i wonder why :

string str = @"//
    // Use a new char[] array of two characters (\r and \n) to break
    // lines from into separate strings. \n Use RemoveEmptyEntries
    // to make sure no empty strings get put in the string array. 
    //";

result text to richTextBox was:

//
    // Use a new char[] array of two characters (\r and \n) to break
    // lines from into separate strings. \n Use RemoveEmptyEntries
    // to make sure no empty strings get put in the string array. 
    //

but

string str = @"//
    // Use a new char[] array of two characters (\r and \n) to break
    // lines from into separate strings."+" \n" + @" Use RemoveEmptyEntries
    // to make sure no empty strings get put in the string array. 
    //";

result text to richTextBox was:

//
    // Use a new char[] array of two characters (\r and \n) to break
    // lines from into separate strings. 
 Use RemoveEmptyEntries
    // to make sure no empty strings get put in the string array. 
    //

Answer 1

There is no literal @ before your central string " \\n" The equivalent would be

string str = @"//
// Use a new char[] array of two characters (\r and \n) to break
// lines from into separate strings."+ @" \n" + @" Use RemoveEmptyEntries
// to make sure no empty strings get put in the string array. 
//";

\\ is an escape character in normal strings, but string literals use the content exactly as is, except in the case of " which is escaped as ""

Answer 2

Because there is no @ before the "\\n" in you second example. Any escape sequence after @ (verbatim string literal) will be ignored. In your first example it was ignored but not in the second.

Have a look at this: http://msdn.microsoft.com/en-us/library/aa691090(v=vs.71).aspx