How do I preg replace the following at linux command line
Question
How do I preg replace the following at linux command line
<link rel="pear-icon" sizes="100" href="../../pear.png" />
I want to preg replace away the ../../ to make it become
<link rel="pear-icon" sizes="100" href="pear.png" />
Because there a lot of ../../ in my link, how do i mass preg replace and recursive on all file that contain this ../../
Thanks !
1 answers
solution1
1 2014-11-20 13:09:29
Something like this should do the trick:
find . -name "*.php" -print | xargs sed -i 's/"\.\.\/\.\.\/pear\.png/"pear\.png/g'
Try it first on 1 file though... didnt test this myself
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