i go from my front(login.php) to my back(loginback.php) i want to send an array of data from the back to the front. When i do this all it prints is "Array", so i tried using print_r to see what was in it and it still just says "Array".
login
<?php
if(isset($_POST['submit']))
{
include_once("dbconnect.php");
$name = $_POST['name'];
$pass = $_POST['pass'];
$account = $_POST['account'];
$post = 'name='.$name.'&pass='.$pass.'&account='.$account;
$url = "#####/Middle/loginBack.php";
$ch = curl_init();//initialize
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURL_POST, true); //true = 1
curl_setopt($ch, CURLOPT_POSTFIELDS, $post);//post is the date of name value pair
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);//get data bak = true
$response = curl_exec($ch); //execute and get back data
curl_close($ch);// close all curl connections
print_r($response);
?>
loginback
<?php
include ('dbconnect.php');
$name = $_POST['name'];
$pass = $_POST['pass'];
$account = $_POST['account'];
$sql = " SELECT id, Username, Password FROM studentAccounts WHERE Username = '$name' ";
$query = mysqli_query($dbCon, $sql);
$row = mysqli_fetch_row($query);
$dbid = $row[0];
$dbName = $row[1];
$dbPass = $row[2];
$num = 100;
$myArray = array($num, $name, $dbid);
echo $myArray;
?>
you can use the below code to send array to the desired url using post method
curl_setopt_array($curl, array( CURLOPT_RETURNTRANSFER => 1, CURLOPT_URL => AUTHENTICATIONURL, CURLOPT_USERAGENT => 'user Sample cURL Request', CURLOPT_POST => 1, CURLOPT_POSTFIELDS => array( '0' => 'ram', '1' => 'sham', '2'=> 'geta', '3'=>'so on' ) ));
Try this code snippet and $post = 'name='.$name.'&pass='.$pass.'&account='.$account;
This is not an array it's just a string
It's not possible to print an array with echo. In your case since you want to grab the data from another server, you would need to send data in a controlled from. JSON would work fine here.
Change your echo to something like this
echo json_encode($myArray);
then you should see the JSON string representing your array. Now on the other side, you would use json_decode to convert it back to an array.
EDIT : Just to make it clear, if you would replace
print_r($response);
with
print_r(json_decode($response));
i do think you will see your data.
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