I am getting a little tripped up with a SQL query. Here is some background.
Schema:
Product(pid, price, color),
Order(cid, pid, quantity),
Customer(cid, name, age)
I want to get the pid of the most ordered product (greatest quantity).
I have managed to determine the max value with:
Select Max(total)
From (Select Sum(quantity) as total
From Orders Group By pid) as Totals
but I am getting stuck trying to match which products are in this subquery. Here is what I have tried:
Select pid, SUM(quantity) as q
From Orders
Where q in (
Select Max(total)
From (Select Sum(quantity) as total
From Orders
Group By pid) as Totals
)
Group By pid
This says that q is an unknown column.
Any suggestions on how I could do this or do it better?
you can do a JOIN
along with GROUP BY
like
select p.*
from product p
join
(select pid from Order
group by pid having quantity = max(quantity)
) tab on p.pid = tab.pid;
In your posted query it's erroring q is an unknown column
cause q
is a column alias which you are trying to use in WHERE
condition; which is not allowed.
You should be able to simply include the PID
in the original query because you are grouping on it. Then ORDER BY
and and get only the top result using LIMIT 1
.
SELECT
pid
,Sum(quantity) as total
FROM
Orders
GROUP BY
pid
ORDER BY
Sum(quantity)
LIMIT 1
Here's one way you can do it using a subquery with limit
:
select o.pid, sum(o.quantity)
from `order` o
group by o.pid
having sum(o.quantity) =
(
select sum(quantity)
from `order`
group by pid
order by sum(quantity) desc
limit 1
)
If you want only one most ordered product, then Karl's answer is fine. If you want all that have the same quantity, then:
select pid, sum(quantity) as quantity
from orders o
group by pid
having sum(quantity) = (select max(quantity)
from (select sum(quantity) as quantity
from orders o
group by pid
) q
);
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