Ajax json response not getting appended to the page

Question

I want to append a json object to the page. I get it successfully via ajax, but it's not showing up.

<form onsubmit="return false;">
{% csrf_token %}
   Search:<input type="text" name="artist" id="artist" />
    <button class="updateButton" onclick="createlist()">submit</button>
</form>

function createlist(){
$.ajax({
    type: "POST",
    url: "/rest/",
    dataType: "json",
    data: {
        artist: $('#artist').val()
    },
    headers: {
        'X-CSRFTOKEN': "{{ csrf_token }}",
    },
    success: function(data){
        $('#output').html(data); //also tried data.content
    }
});
}

The response appears to be in one long escaped string when I view the response and preview in devtools.

"[{\"fields\": {\"artist\": \"Leonardo da Vinci\", \"link\": \"https://trove2.storage.googleapis.com/leonardo-da-vinci/galloping-rider-and-other-figures.jpg\", \"title\": \"Galloping Rider and other figures\"}, \"model\": \"serve.art\", \"pk\": 63057}

How can I wrangle this into something usable?

Answer 1

use

JSON.parse

and you'll get the data.

https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Global_Objects/JSON/parse

Answer 2

No you cannot append an object to a HTML element.

Don't parse the JSON , just append in the format( string ) as you are getting.

I have tried and successfully appended to the HTML element but in the string format.

Answer 3

you should try like this:

 var output=""; var data="[{\\"fields\\": {\\"artist\\": \\"Leonardo da Vinci\\", \\"link\\": \\"https://trove2.storage.googleapis.com/leonardo-da-vinci/galloping-rider-and-other-figures.jpg\\", \\"title\\": \\"Galloping Rider and other figures\\"}, \\"model\\": \\"serve.art\\", \\"pk\\": 63057}]"; data = JSON.parse(data) for(x in data){ console.log(data[x]); output=output+"Artist:"+data[x].fields.artist+"<br>"+"Link:"+data[x].fields.link+"<br>"+"Title:"+data[x].fields.title+"<br>"+"Model:"+data[x].model+"<br>"+"PK:"+data[x].pk+"<br>"; } $('#output').html(output); 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <div id="output"></div>