You can use the LEFT function in SQL Server to get the decade from the year. The decade is the first 3 digits of the year. You can group by the decade and then count the number of movies. If you sort, or order, the results by the number of movies - the decade with the largest number of movies will be at the top. For example:
select
count(id) as number_of_movies,
left(cast([year] as varchar(4)), 3) + '0s' as decade
from movies
group by left(cast([year] as varchar(4)), 3)
order by number_of_movies desc
An alternative to the string approach is to use integer division to get the decade:
SELECT [Year]/10*10 as [Decade]
, COUNT(*) as [CountMovies]
FROM Movies
GROUP BY [Year]/10*10
ORDER BY [CountMovies] DESC
This returns all, ordered by the decade(s) with the most movies. You could add a TOP (1) to only get the top, but then you'd need to consider tiebreaker scenarios to ensure you get deterministic results.
select substring(cast([year] as varchar), 1, 3) as Decade,
Count(1) [Count]
from Movies
group by substring(cast([year] as varchar), 1, 3)
order by 2 desc
SELECT floor(Year(getdate())/10)*10
, floor(year('5/11/2004')/10)*10
, floor(Year('7/23/1689')/10)*10
, floor(Year('7/09/1989')/10)*10
Despite being an old question I found this solution via trying
DATE_PART('decade',(year::date)) AS decade,
DATE_TRUNC('decade',(year::date)) AS decade_truncated,
also works for
DATE_PART('century',(year::date)) AS decade,
DATE_TRUNC('century',(year::date)) AS decade_truncated,
In my case, I am having year
as a string column. To get the movies grouped by decades,
SELECT DISTINCT NUMRANGE(
CAST(FLOOR(CAST(year AS INT)/ 10) * 10 AS INT),
CAST((FLOOR(CAST(year AS INT)/ 10) * 10) + 9 AS INT)
) AS "decades", COUNT(*) AS "movie_count"
FROM movies
WHERE year IS NOT NULL AND year != ''
GROUP BY decades
ORDER BY movie_count DESC;
This gives the number of movies in that decade. Hope this one helps someone...
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