How to use String.Replace

Question

Quick question:

I have this String m_Author, m_Editor But I have some weird ID stuff within the string so if I do a WriteLine it will look like:

'16;#Luca Hostettler'

I know I can do the following:

    string author = m_Author.Replace("16;#", "");
    string editor = m_Editor.Replace("16;#", "");

And after that I will just have the name, But I think in future I will have other people and other ID's.

So the question: Can I tell the String.Replace("#AndEverythingBeforeThat", "") So i could also have

'14;#Luca Hostettler'

'15;#Hans Meier'

And would get the Output: Luca Hostettler, Hans Meier, without changing the code manually to m_Editor.Replace("14;#", ""), m_Editor.Replace("15;#", "") ...?

Answer 1

It sounds like you want a regex of "at least one digit, then semi-colon and hash", with an anchor for "only at the start of the string":

string author = Regex.Replace(m_Author, @"^\d+;#", "");

Or to make it more reusable:

private static readonly Regex IdentifierMatcher = new Regex(@"^\d+;#");
...
string author = IdentifierMatcher.Replace(m_Author, "");
string editor = IdentifierMatcher.Repalce(m_Editor, "");

Note that there may be different appropriate solutions if:

• The ID can be non-numeric
• There may be other ignorable parts and you only want the value after the last hash

Answer 2

You could use regex or (what i'd prefer) IndexOf + Substring :

int indexOfHash = m_Author.IndexOf("#");
if(indexOfHash >= 0)
{
    string author = m_Author.Substring(indexOfHash + 1);
}

Answer 3

要不就，

var author = m_Author.Split('#').Last();

Answer 4

您可以使用string.Split（）函数使用＃拆分字符串，这将为您提供两个字符串，首先是＃之前的所有内容，然后是＃之后的所有内容

Answer 5

use String.Format

    int number=5;
    string userId = String.Format("{0};#",number)
    string author = m_Author.Replace(userId, "");

Answer 6

If all you want to do is filter out everything that is not a letter or space, try:

var originalName = "#123;Firstname Lastname";
var filteredName = new string(originalName
                                 .Where(c => Char.IsLetter(c) || 
                                             Char.IsWhiteSpace(c))
                                 .ToArray());

The example will produce Firstname Lastname

Answer 7

List<char> originalName = "15;#Hans Meier".ToList();
string newString = string.Concat(originalName.Where(x => originalName.IndexOf(x) > originalName.IndexOf('#')).ToList());