I would like to extract from the text:
CHEXA* 99001088 99001001 99001143 99001179*00072A1
*00072A1 99001047 99001104 99001144 99001180*00072A2
*00072A2 99001048 99001105
RBE3* 99001089 99001001 123*00072A5
*00072A50.11263443595303 123 6001515.041507658257159*00072A6
*00072A6 60016620.61808377914687 123 6001542
CHEXA* 99001086 99001001 99001128 99001095*0007299
*0007299 99001081 99001171 *000729B
*000729B
this portion:
RBE3* 99001089 99001001 123*00072A5
*00072A50.11263443595303 123 6001515.041507658257159*00072A6
*00072A6 60016620.61808377914687 123 6001542
put it in a file and delete it from the initial file, which will look this way afterwards:
CHEXA* 99001088 99001001 99001143 99001179*00072A1
*00072A1 99001047 99001104 99001144 99001180*00072A2
*00072A2 99001048 99001105
CHEXA* 99001086 99001001 99001128 99001095*0007299
*0007299 99001081 99001171 *000729B
*000729B
What I tried was:
sed '/RBE3\*/,/\*/d'
but unfortunately it will stop after the first occurrence of . But the purpose is to delete all lines after RBE3 is met, which starts with * and this one will delete only one line. Thank you
import os
keep = True
with open(pathToInput) as infile, open(pathToOutput, 'w') as outfile, open(pathToSave) as savefile:
for line in infile:
if line.startswith("RBE3"):
keep = False
elif not line.startswith("*"):
keep = True
if keep:
outfile.write(line)
else:
savefile.write(line)
os.remove(pathToInput)
os.rename(pathToOutput, pathToInput)
RBE3\*[^\n]*\n(?:\*[^\n]*\n)*
Try this.Replace with empty string
.See demo.
https://regex101.com/r/vN3sH3/3
print re.sub(r"RBE3\*[^\n]*\n(?:\*[^\n]*\n)*","",text)
Through python's re
module.
import re
with open('/path/to/the/infile') as infile, open('/path/to/the/outfile', 'w+') as out:
foo = infile.read()
out.write(re.sub(r'(?s)RBE3\*.*?\n(?!\*)', r'', foo))
Update:
import re
with open('/path/to/the/infile') as infile, open('/path/to/the/outfile', 'w+') as out, open('/path/to/the/file/to/save/deleted/lines', 'w+') as save:
foo = infile.read()
out.write(re.sub(r'(?s)(.*?\n)(RBE3\*.*?\n(?!\*))(.*)', r'\1\3', foo))
save.write(re.sub(r'(?s)(.*?\n)(RBE3\*.*?\n(?!\*))(.*)', r'\2', foo))
here's a regexp that will work on Python or PCRE
/(RBE3\\*).+(?=CHEXA\\*)/s
(note that s
modifier is required for it to work.)
A simple python implementation :
import re
import os
inPut = "list"
outPut = "tmp"
regexp = re.compile("(RBE3\*).+(?=CHEXA\*)", re.S)
with open(inPut, 'r') as f:
fileStr = f.read()
match = regexp.search(fileStr).group(0)
ret = re.sub(regexp, "", fileStr)
with open(outPut, 'w') as tmpFile:
tmpFile.write(match)
os.remove(inPut)
os.rename(outPut, inPut)
With awk:
awk -v flag=0 '
/^[^\*]/ { flag = 0 } # clear flag if the line does not start with a *
/^RBE3\*/ { flag = 1 } # except if it is the starting line of an ignored block
flag == 0 { print } # print if ignore flag is not set.
' foo.txt
The nice thing about this is that it is easily extended for the inversion. If you write
awk -v flag=0 -v ignore=0 '
/^[^\*]/ { flag = 0 }
/^RBE3\*/ { flag = 1 }
flag != ignore { print }
' foo.txt
then by replacing ignore=0
with ignore=1
, you can extract the block instead of ignoring it.
using awk:
awk '{if(match($0,"RBE3")>0)flag=0}{if(match($0,"CHEXA")>0)flag=1}{if(flag==1) print $0}' File
output:
CHEXA* 99001088 99001001 99001143 99001179*00072A1
*00072A1 99001047 99001104 99001144 99001180*00072A2
*00072A2 99001048 99001105
CHEXA* 99001086 99001001 99001128 99001095*0007299
*0007299 99001081 99001171 *000729B
*000729B
awk -v key="RBE3" '
index($0,key"*")==1 { f=1; print > "newfile" }
f && /^\*/ { print > "newfile"; next }
{ f=0; print }
' file > tmp && mv tmp file
The above uses index() so it's doing a string rather than regexp comparison so it won't fail if your key contains RE metacharacters, unlike any sed solution.
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