I have a dictionary like this
my_d = {"a": [1, 2, 2, 5, 2],
"b": [2, 1, 2, 4, 5],
"c": [7, 2, 2, 6, 2],
"d": [7, 2, 2, 2, 2]}
I am looking for the keys whose dictionary values contain 2 more than twice. In the example, that would be "a","c","d"
.
You can use count
function in a list comprehension :
>>> my_d = {"a":[1,2,2,5,2],"b":[2,1,2,4,5],"c":[7,2,2,6,2], "d":[7,2,2,2,2]}
>>> [i for i,j in my_d.items() if j.count(2)>2]
['a', 'c', 'd']
my_d.items()
give you the list of the items of your dictionary .
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