How do I make this table?
This is what should be the outcome:
0 1 2 3 4 5 6 7 8 9
1 2 3 4 5 6 7 8 9 0
2 3 4 5 6 7 8 9 0 1
3 4 5 6 7 8 9 0 1 2
4 5 6 7 8 9 0 1 2 3
5 6 7 8 9 0 1 2 3 4
6 7 8 9 0 1 2 3 4 5
7 8 9 0 1 2 3 4 5 6
8 9 0 1 2 3 4 5 6 7
9 0 1 2 3 4 5 6 7 8
And this is the best I could come up with:
for (int i = 0; i < 10; i++)
{
for (int j = 0; j < 10; j++) {
if (i + j < 10) {
System.out.print(i + j);
} else
System.out.print("x");
}
System.out.println();
}
}
}
I simply can't find a solution how to get numbers running again past 9 with the beginning of 0,1,2,3 etc. My code would generate next:
0123456789
123456789x
23456789xx
3456789xxx
456789xxxx
56789xxxxx
6789xxxxxx
789xxxxxxx
89xxxxxxxx
9xxxxxxxxx
You can do:
System.out.print((i + j) % 10);
To turn 10
into 0
, 11
into 1
, etc.
Try this:
for (int i=0; i<10; i++) {
for (int j=i; j<i+10; j++) {
System.out.print(j%10);
}
System.out.println();
}
The key here is to use %
(modulo) operator.
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