简体   繁体   中英

parse json structure from excel sheet into java

i have a data in excel sheet that i need to read in java, i am able to read normal content but not able to read the json structure that i have stored. how can i parse json from excel to java?

public class JavaApplication1 {
public static void main(String[] args) {
    try {
      for (int i=0;i<5;i++)
      {
        FileInputStream fileInputStream = new FileInputStream("C://users/user/Desktop/C.xls");
        HSSFWorkbook workbook = new HSSFWorkbook(fileInputStream);
        HSSFSheet worksheet = workbook.getSheet("POI Worksheet");
        HSSFRow row1 = worksheet.getRow(0);

        HSSFCell cellC1 = row1.getCell((short) 2);
        String c1Val = cellC1.getStringCellValue();
        HSSFCell cellD1 = row1.getCell((short) 3);
        double d1Val = cellD1.getNumericCellValue();
        HSSFCell cellE1 = row1.getCell((short) 4);
        String e1Val = cellE1.getStringCellValue();
        System.out.println("C1: " + c1Val);
        System.out.println("D1: " + d1Val);
        System.out.println("E1: " + e1Val);

        JSONObject obj = new JSONObject();

        obj.put("name", new c1Val);

        System.out.print(obj);
                    }
            } catch (FileNotFoundException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }
  }
}

my excel sheet contains the following json:

     A      B                       C                            D        E  
     1      rap   {"type":"int", "minimum":15, "maximum":58}     240     delhi

this data needs to be read, from column ci need to read a single variable from 15 to 58.. how can i do this?

You can parse JSON into Java object in one line like this,

http://wiki.fasterxml.com/JacksonInFiveMinutes

if your Json String value in c1Val then your json code will be like this.

Map<String,Object> c_data = mapper.readValue(c1Val, Map.class);
String minimum = c_data.get("minimum");
String maximum= c_data.get("maximum");

The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM