I am having a weird behavior when trying to iterate over a plain text file:
#!/bin/bash
sed -n "5,5p" test.tmp
while read linea in
do
echo $linea
done < test.tmp
The thing is that from the first sed I get what I expected, but from the while loop I don't:
./test.sh
(5) Sorgo DICOTILEDONEAS 1,5-2 l/ha 15
(1)
(2)
(3)
(4)
(5)
(6)
I am attaching both files in order to help clarifying what is happening here:
Thanks in advance
What I would do :
#!/bin/bash
while IFS= read -r linea; do
printf '%s\n' "$linea"
done < <(sed -n "5,5p" test.tmp)
< <( )
is a process substitution, check
http://mywiki.wooledge.org/ProcessSubstitution
http://wiki.bash-hackers.org/syntax/expansion/proc_subst
"Double quote" every literal that contains spaces/metacharacters and every expansion: "$var"
, "$(command "$var")"
, "${array[@]}"
, "a & b"
. Use 'single quotes'
for code or literal $'s: 'Costs $5 US'
, ssh host 'echo "$HOSTNAME"'
. See
http://mywiki.wooledge.org/Quotes
http://mywiki.wooledge.org/Arguments
http://wiki.bash-hackers.org/syntax/words
I finally found what was going on. There was an extra "in" within the while statement. Probably I mixed two different kind of whiles.
Where I had:
while read linea in do echo $linea done < test.tmp
It should read:
while read linea; ## in removed and ; added do echo $linea done < test.tmp
Thanks again
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