I am trying to decode multiple json files to a database I have created a folder which has 2 json files in it but I get the error as
failed to open stream: Permission denied
using following code
$json = file_get_contents('C:\Users\Richard\Desktop\JSON_Files');
code implemented as per answers
<?php
$con=mysqli_connect("localhost","root","","json_map");
$response = array();
$res=array();
$json='';
foreach (glob("C:\xampp\htdocs\laravel\awsconfig\app\JSON_Files\*.json") as $filename) {
$json.= file_get_contents($filename);
}
if($json!=null){
$decoded=json_decode($json,true);
//$decode= var_dump($decoded);
//$ss=$decode["array"];
//echo $decoded['number'];
if(is_array($decoded["configurationItems"]))
{
foreach($decoded["configurationItems"] as $configurationItems)
//for($i=0;$i>sizeof($decoded["configurationItems"]);$i++)
{
$configurationItemVersion=$configurationItems["configurationItemVersion"];
echo "<br />","configuration_Item_Version:",$configurationItemVersion,"<br />";
$configurationItemCaptureTime=$configurationItems["configurationItemCaptureTime"];
echo "configurationItemCaptureTime:",$configurationItemCaptureTime,"<br />";
$configurationStateId=$configurationItems["configurationStateId"];
echo "configurationStateId:",$configurationStateId,"<br />";
$awsAccountId=$configurationItems["awsAccountId"];
echo "awsAccountId:",$awsAccountId,"<br />";
$configurationItemStatus=$configurationItems["configurationItemStatus"];
echo "configurationItemStatus:",$configurationItemStatus,"<br />";
$resourceId=$configurationItems["resourceId"];
echo "resourceId:",$resourceId,"<br />";
$ARN=$configurationItems["ARN"];
echo "ARN:",$ARN,"<br />";
$awsRegion=$configurationItems["awsRegion"];
echo "awsRegion:",$awsRegion,"<br />";
$availabilityZone=$configurationItems["availabilityZone"];
echo "availabilityZone:",$availabilityZone,"<br />";
$configurationStateMd5Hash=$configurationItems["configurationStateMd5Hash"];
echo "configurationStateMd5Hash:",$configurationStateMd5Hash,"<br />";
$resourceType=$configurationItems["resourceType"];
echo "resourceType:",$resourceType,"<br />";
$resourceCreationTime=$configurationItems["resourceCreationTime"];
echo "resourceCreationTime:",$resourceCreationTime,"<br />";
$result = mysqli_query($con, "INSERT INTO configuration_item(configuration_item_version,configuration_item_capture_time,configuration_state_id, aws_account_id, configuration_item_status, resource_id, arn, aws_region, availability_zone,configuration_state_md5_hash, resource_type, resource_creation_time)
VALUES('$configurationItemVersion','$configurationItemCaptureTime','$configurationStateId','$awsAccountId','$configurationItemStatus','$resourceId','$ARN','$awsRegion','$availabilityZone','$configurationStateMd5Hash','$resourceType','$resourceCreationTime' )")or die("Insert Failed ".((is_object($con)) ? mysqli_error($con) : (($___mysqli_res = mysqli_connect_error()) ? $___mysqli_res : false)));;
}
// check if row inserted or not
if ($result) {
// successfully inserted into database
$response["code"] = 1;
$response["message"] = "successfully stored configuration items ";
// echoing JSON response
echo json_encode($response);
} else {
// failed to insert row
$response["code"] = 2;
$response["message"] = "Oops! An error occurred.";
// echoing JSON response
echo json_encode($response);
}
}
}
?>
You can't open file on C:\\Users\\Richard\\Desktop\\ Copy it into your app folder: for exemple /mysite/html/jsonfiles/
<?php
$json='';
foreach (glob("/mysite/html/jsonfiles/*.json") as $filename) {
$json.= file_get_contents($filename);
}
the $json var contains all your json code... Adpat code...
You need to read the files individually, you can use the glob function try the following:
// Specify file pattern
$json_files = glob("C:\\Users\\Richard\\Desktop\\JSON_Files\\*.json");
$all_files_contents = '';
// Iterate over the found files
foreach($json_files as $json_file) {
$all_files_contents .= file_get_contents($json_file);
}
At the end in $all_files_contents
you will have all files contents.
First of all, I am guessing that you are trying to open a file existing in the client side (your local computer and not the server).
PHP code is server-side code. This means that you are trying to open a file in the server and not the computer that is the client. You probably can not open the client file server-side, but it also seems you do not have the permissions to open the file even in the client (take a look here ).
What you can simply do is put the file into an application folder (server-side) and then try to open it, as Imaginaerum mentioned.
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