I'm trying to remove all the rows that have the same value in the "lan" column of my dataframe but different value for my "id" column (but not vice-versa).
Using an example dataset:
require(dplyr)
t <- structure(list(id = c(1L, 2L, 2L, 3L, 3L, 4L, 4L, 4L, 4L, 4L,
4L), lan = structure(c(1L, 2L, 3L, 4L, 4L, 5L, 5L, 5L, 6L, 1L,
7L), .Label = c("a", "b", "c", "d", "e", "f", "g"), class = "factor"),
value = c(0.22988498, 0.848989831, 0.538065821, 0.916571913,
0.304183372, 0.983348167, 0.356128559, 0.054102854, 0.400934593,
0.001026817, 0.488452667)), .Names = c("id", "lan", "value"
), class = "data.frame", row.names = c(NA, -11L))
t
I need to get rid of rows 1 and 10 because they have the same lan (a) but different id.
I've tried the following, without success:
a<-t[(!duplicated(t$id)),]
c<-a[duplicated(a$lan)|duplicated(a$lan, fromLast=TRUE),]
d<-t[!(t$lan %in% c$lan),]
Thanks for your help!
And an alternative using dplyr
:
t2 <- t %>%
group_by(lan,id) %>%
summarise(value=sum(value)) %>%
group_by(lan) %>%
summarise(number=n()) %>%
filter(number>1) %>%
select(lan)
> t[!t$lan %in% t2$lan ,]
id lan value
2 2 b 0.84898983
3 2 c 0.53806582
4 3 d 0.91657191
5 3 d 0.30418337
6 4 e 0.98334817
7 4 e 0.35612856
8 4 e 0.05410285
9 4 f 0.40093459
11 4 g 0.48845267
You could use duplicated
on "lan", to get the logical index of all elements that are duplicates, repeat the same with both columns together ('id', 'lan'), to get the elements not duplicated, check which of these elements are TRUE in both cases, negate, and subset.
indx1 <- with(t, duplicated(lan)|duplicated(lan,fromLast=TRUE))
indx2 <- !(duplicated(t[1:2])|duplicated(t[1:2],fromLast=TRUE))
t[!(indx1 & indx2),]
# id lan value
#2 2 b 0.84898983
#3 2 c 0.53806582
#4 3 d 0.91657191
#5 3 d 0.30418337
#6 4 e 0.98334817
#7 4 e 0.35612856
#8 4 e 0.05410285
#9 4 f 0.40093459
#11 4 g 0.48845267
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