How to return inserted row in mysql using json format?

Question

I have to return the inserted row which is just inserted into json format in the same php code. In this row booking_id is auto generated key, and other information like customer_Name, customer_Email, customer_id. So How I will return inserted row with additional column booking_id (auto-generated)?.

please Note this question is same as but I forget to asked returning row but asked only returning id. sorry for that. check here

script

<script>
    $(document).ready(function(){
        $("#register-form").validate({
            rules: {
                userName: "required",                           
                email: {
                    required: true,
                    email: true
                },                                              
                userContactNumber: "required"                       
            },
            messages: {
                userName: "Please enter your Name",
                userContactNumber: "Please enter your Mobile number",                           
                email: "Please enter a valid email address",                                           
            },
            submitHandler: function(form) {

                var uName = $('#userName').val();   
                var mailId = $('#email').val();                 
                var mobNum = $('#userContactNumber').val();

                $.ajax({                
                    url:"http://localhost/bookRoom/book.php",
                    type:"POST",
                    dataType:"json",
                    data:{type:"booking", Name:uName, Email:mailId,  Mob_Num:mobNum},                                   
                    ContentType:"application/json",
                    success: function(response){                            
                        window.location.href = 'BookingConformation.html';
                    },
                    error: function(err){                           
                        window.location.href = 'error.html';
                    }
                });
                return false; // block regular submit
            }
        });
    });
</script>

server code

<?php
    header('Access-Control-Allow-Origin: *');//Should work in Cross Domaim ajax Calling request
    mysql_connect("localhost","root","2190");
    mysql_select_db("hotels");

    if(isset($_POST['type']))
    {
        if($_POST['type']=="booking"){
            $name = $_POST ['Name'];               
            $mobile = $_POST ['Mob_Num'];
            $mail = $_POST ['Email'];               
            $query1 = "insert into customer(userName, userContactNumber, email) values('$name','$mobile','$mail')";
            $query2 = "insert into booking(cust_name, cust_email, cust_mobile) values('$name', '$mail','$mobile')";         

            $result1=mysql_query($query1);

            $result2=mysql_query($query2);
            echo json_encode($result1);
        }
    }
    else{
        echo "Invalid format";
    }
?>

Answer 1

You can access the id that was auto generated in the insert operation with the mysql_insert_id() function

To return it, just create an array with the data you used in the insert and the retrieved id. You can then return the array using json_enode.

Answer 2

use it. i think this is helpful for you

$id = mysql_insert_id();

Answer 3

use: mysql_insert_id() or mysqli_insert_id() to return the booking ID.

Note: while using mysql_insert_id be careful as it's depreciated in php 5.5 and will be removed in future

$id = mysql_insert_id();
echo json_encode($id);

Then in your ajax success function use php file instead of html and pass this booking in a url query string and use this booking ID in your booking.php and write a query to fetch that row :

success: function(response){                            
                        window.location.href = "BookingConformation.php?bookingID='+response+'";
                    }

Then in your bookingConfirmation.php file use GET method to fetch this variable:

$bookingID=$_GET['bookingID'];
$query1= "select * from bookin where b_id =".$bookingID;
$result = mysql_query($query1);    
var_dump($result); //gives your array of insterd row