I have created a function to split paths into lists of directories in python like so:
splitAllPaths = lambda path: flatten([[splitAllPaths(start), end] if start else end for (start, end) in [os.path.split(path)]])
with this helper function:
#these only work one directory deep
def flatten(list_of_lists):
return list(itertools.chain.from_iterable(list_of_lists))
The output from this function looks like so:
> splitAllPaths('./dirname/dirname2/foo.bar')
[[[['.'], 'dirname'], 'dirname2'], 'foo.bar']
now I want this as a flat list. my attempts are as follows (with the output):
> flatten(splitAllPaths('./diname/dirname2/foo.bar'))
['.', 'd', 'i', 'r', 'n', 'a', 'm', 'e', 'd', 'i', 'r', 'n', 'a', 'm', 'e', '2', 'f', 'o', 'o', '.', 'b', 'a', 'r']
and
> reduce(list.__add__, (list(mi) for mi in splitAllPaths('./dirname/dirname2/foo.bar')))
me2/foo.bar')))
[[['.'], 'dirname'], 'dirname2', 'f', 'o', 'o', '.', 'b', 'a', 'r']
How do I unfold this list correctly (I would also welcome any suggestions for how to improve my splitAllPaths
function)?
This a less general answer, but it solves your original problem -- although its elegance is debatable.
The main idea is the fact that generating a list with the reversed (as in ['file', 'user', 'home', '/']
order is quite easy, so you can just create that and reverse it in the end. So it boils down to:
def split_paths(path):
def split_paths_reverse(path):
head, tail = os.path.split(path)
while head and tail:
yield tail
head, tail = os.path.split(head)
yield head
return reversed(tuple(split_paths_reverse(path)))
Example:
test = '/home/user/file.txt'
print(list(split_paths(test)))
['/', 'home', 'user', 'file.txt']
You could also avoid the explicit reversing part by putting each element in a stack and then removing them, but that's up to you.
Sortherst way that comes in mind would be:
listoflists = [[[['.'], 'dirname'], 'dirname2'], 'foo.bar']
str(listoflists).translate(None,"[]'").split(',')
I solved this by writing a (non-general) foldr. I think better, more practical solutions are provided by @L3viathan in the comments.
attempt = lambda list: attempt(list[0] + list[1:]) if len(list[0]) > 1 else list[0] + list[1:]
Output
> attempt([[[['.'], 'dirname'], 'dirname2'], 'foo.bar'])
['.', 'dirname', 'dirname2', 'foo.bar']
I've also now written it in terms of a general foldr1
> foldr1 = lambda func, list: foldr1(func, func(list[0], list[1:])) if len(list[0]) > 1 else func(list[0], list[1:])
> foldr1(list.__add__, [[[['.'], 'dirname'], 'dirname2'], 'foo.bar'])
['.', 'dirname', 'dirname2', 'foo.bar']
NOTE: Could someone more familiar than me confirm that this is a foldr and not a foldl (I often get them confused).
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