Python requests.exception.ConnectionError: connection aborted “BadStatusLine”

Question

I am trying to use the Python requests module to issue Http GET commands to access some REST based APIs. The urls are working fine on a RESTClient but when I use the same url in python, I get a connection error.

The code I am trying to execute is:

payload={"mac":new_mac,"token":token}
userloginurl="http://192.168.1.40:9119/uid"
r=requests.get(userloginurl,params=payload)
print(r.url)

If I test this url using RESTClient, I get a 200 OK status code in the response header along with some more fields. But this is not working with python requests. The traceback of the error is shown below:

Traceback (most recent call last):
File "getAPids.py", line 34, in <module>
r=requests.get(userloginurl,params=payload)
  File "C:\Users\garvitab\python\lib\site-packages\requests\api.py", line 65, in
 get
return request('get', url, **kwargs)
File "C:\Users\garvitab\python\lib\site-packages\requests\api.py", line 49, in
request
response = session.request(method=method, url=url, **kwargs)
File "C:\Users\garvitab\python\lib\site-packages\requests\sessions.py", line 4
61, in request
resp = self.send(prep, **send_kwargs)
File "C:\Users\garvitab\python\lib\site-packages\requests\sessions.py", line 5
73, in send
r = adapter.send(request, **kwargs)
 File "C:\Users\garvitab\python\lib\site-packages\requests\adapters.py", line 4
15, in send
raise ConnectionError(err, request=request)
requests.exceptions.ConnectionError: ('Connection aborted.', BadStatusLine("''",
))

I looked up for the cause of the problem. Possibly, the response received is not formatted correctly. Is there a way to handle this problem?

Thanks in advance.

Answer 1

The problem was with the url. This connection was meant to be established over https and I was using http in the python script. Hence the issue.

Answer 2

Have you actually checked, what gets send over the wire? I suppose you might have to convert your dictionary to a JSON string by yourself, or use the json= keyword instead of payload= . See http://docs.python-requests.org/en/latest/user/quickstart/#custom-headers for details. This may do the trick:

import json
payload = json.dumps({"mac":new_mac,"token":token})
userloginurl = "http://192.168.1.40:9119/uid"
r = requests.get(userloginurl, data=payload)
print(r.url)

Answer 3

I was getting the same error and spent hours on it. I found that you cannot call the flask server in a client using "Localhost". It has to be "127.0.0.1"

#server
from flask import Flask
app = Flask(__name__)

@app.route('/')
def hello_world():
   return 'Hello World'

if __name__ == '__main__':
   app.run(debug=True)

Now the client causing the error:

#client
import requests
x = requests.get('http://localhost:5000') # change it to 127.0.0.1
print(x.text)