Pattern in java using numbers

Question

I am trying to print the following pattern but don't get the logic how to.. Can you please help me out.. I am using BlueJ and this is my first question so I am not sure what is required.

                1
               2 2
             3 3 3 3
           4 4 4 4 4 4

Thank You in advance.

i have tried this

public class Program92
{
    public static void main()
    {
        for(int x=1;x<=5;x++)
        {
            for(int j=1;j<=x;j++)
             System.out.print(x);
            System.out.println();
        }
    }
}

but could only get

                1
                22
                333
                4444
                55555

Answer 1

Since this seems to be homework, see if you can manage to get it to build a right angled triangle with those numbers, so 1 on top, 2 2 's beneath it, 4 3 's beneath that, etc:

1
2 2
3 3 3 3
4 4 4 4 4 4

Once that you manage that, all that you would need to do would be to figure out how many white space values you need to add before each number.

Answer 2

you can try this snippet of code as it will print first blank space then your number. and also after every number there is blank space.

public static void main(String[] args) {
    int l= 5;int k=0;
     for(int x=1;x<5;x++)
        {
         for(int i=l*2-1;i>0;i--)
         {  
            if(x == 1 && i ==1)
                break;
            System.out.print(" "); 
         }
         System.out.print(x); 
         System.out.print(" "); 
         for(int i=1;i<x*2-2;i++)
         {
             System.out.print(x); 
             System.out.print(" "); 
         }
         System.out.println();
         l--;
        }

        }

Answer 3

Try this:

public class program98
{
public static void main()
{
System.out.print("     "+"1");//5 spaces int the blank
for(int i=1;i<=4;i++)
{
 for(int s=6;s>1;s--)
   {System.out.print(" ");//1 space
    }
  for(int j=1;j<1;j++)
    {System,out.print(i);
     }
    for(int j=1;j<1;j++)
      {System.out.print(i);//prints this twice. Hence,instead of once,the number of times it prints is double
       }
         System.out.println(" ");//1 space
        }
       }
      }