I am playing around with the omp task function, and has encountered a problem. I have the following code:
void function1(int n, int j)
{
//Serial part
#pragma omp parallel
{
#pragma omp single nowait
{
//execcute function1() for every n
for (i=0; i<n; i++)
{
//create a task for computing only large numbers of n
if (i <= 10)
//execute serial
else
#pragma omp task
//call function again
function1(n, j+1);
printf("task id:\n", omp_get_thread_num());
}
}
}
}
Right now the code will produce the correct result, but the performance is much slower than the original serial version. After some investigation I found that all the tasks are executed in thread 0 regardless there are 4 threads running in total. Does anyone know what's going on here? Thanks in advance!
The omp single nowait
pragma means that the following block is to be executed by a single thread. In this case that means that your entire loop is executed by one thread. This should resolve your issue:
void function1(int n, int j)
{
//Serial part
#pragma omp parallel
{
//execcute function1() for every n
for (i=0; i<n; i++) //Notice this is outside the pragma
{
#pragma omp single nowait //Notice this is inside the loop
{
//create a task for computing only large numbers of n
if (i <= 10)
//execute serial
else
#pragma omp task
//call function again
function1(n, j+1);
printf("task id:\n", omp_get_thread_num());
}
}
}
}
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