Hello i need to make a bash script that will read from a file and then add the numbers in the file. For example, the file im reading would read as:
cat samplefile.txt
1
2
3
4
The script will use the file name as an argument and then add those numbers and print out the sum. Im stuck on how i would go about reading the integers from the file and then storing them in a variable. So far what i have is the following:
#! /bin/bash
file="$1" #first arg is used for file
sum=0 #declaring sum
readnums #declaring var to store read ints
if [! -e $file] ; do #checking if files exists
echo "$file does not exist"
exit 0
fi
while read line ; do
do < $file
exit
What's the problem? Your code looks fine, except readnums
is not a valid command name, and you need spaces inside the square brackets in the if
condition. (Oh and "$file"
should properly be inside double quotes.)
#!/bin/bash
file=$1
sum=0
if ! [ -e "$file" ] ; do # spaces inside square brackets
echo "$0: $file does not exist" >&2 # error message includes $0 and goes to stderr
exit 1 # exit code is non-zero for error
fi
while read line ; do
sum=$((sum + "$line"))
do < "$file"
printf 'Sum is %d\n' "$sum"
# exit # not useful; script will exit anyway
However, the shell is not traditionally a very good tool for arithmetic. Maybe try something like
awk '{ sum += $1 } END { print "Sum is", sum }' "$file"
perhaps inside a snippet of shell script to check that the file exists, etc (though you'll get a reasonably useful error message from Awk in that case anyway).
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