I'm doing Standard Deviation with 10 random numbers. I have to find the average of the 10 numbers. I then subtract the average and square it. I then have to find the average again and find the square root of the average. For example:
2, 4, 4, 4, 5, 5, 7, 9
These eight digits have a mean (average) of 5:
(2 + 4 + 4 + 4 + 5 + 5 + 7 + 9) / 8 = 5
First, calculate the difference of each element from the mean and square the results of each:
( 2 - 5 )2 = 9
( 4 - 5 )2 = 1
( 4 - 5 )2 = 1
( 4 - 5 )2 = 1
( 5 - 5 )2 = 0
( 5 - 5 )2 = 0
( 7 - 5 )2 = 4
( 9 - 5 )2 = 16
Next, calculate the mean (average) of these values and then take the square root:
Math.sqrt( (9 + 1 + 1 + 1 + 0 + 0 + 4 + 16) / 8) = 2
Thus, the standard deviation from the array 2, 4, 4, 4, 5, 5, 7, 9 is 2.
The problem I keep running into is I cant figure out how to add the numbers again the second time. It adds the original 10 random numbers.
public class StandardDeviation {
public static void main(String[] args) {
//Create array
int [] array = new int [10];
//Generate 10 random numbers
for (int i = 0; i < array.length; i++) {
array [i] = (int)(Math.random() * 100);
System.out.println(array[i]);
}
//Add 10 numbers together
int sum = 0;
for (int i : array) {
sum += i;
}
//Find Average
int average = sum/10;
System.out.println("Average: " + average);
//create New Array
int [] variance = new int [array.length];
for (int i = 0; i < variance.length; i++) {
variance[i] = array[i];
}
//Subtract Average and Square it
int sum2 = 0;
for (int i: variance) {
i -= average;
i *= i;
System.out.println(i);
}
System.out.println("Sum: " + addNumbers(variance));
}
public static int addNumbers (int [] variance) {
int total = 0;
for (int i = 0; i < variance.length; i++) {
total += variance[i];
}
return total;
}
}
Try this for your "//Subtract Average and Square it" for loop:
for (int i = 0; i < variance.length; ++i) {
variance[i] -= average;
variance[i] *= variance[i];
System.out.println(variance[i]);
}
You are not currently updating the value stored in the array.
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