Regular expression to get number between two square brackets

Question

Hi I need to get a string inside 2 pair of square brackets in javascript using regular expressions.

here is my string [[12]],23,asd

So far what I tried is using this pattern ' \\[\\[[\\d]+\\]\\] '

and I need to get the value 12 using regular expressions

Answer 1

You can use the following regex,

\[\[(\d+)\]\]

This will extract 12 from [[12]],23,asd

It uses capture groups concept

Answer 2

\[\[(\d+)\]\]

Try this.Grab the capture or group 1.See demo.

var re = /\[\[(\d+)\]\]/gs;
var str = '[[12]],23,asd';
var m;

while ((m = re.exec(str)) != null) {
if (m.index === re.lastIndex) {
re.lastIndex++;
}
// View your result using the m-variable.
// eg m[0] etc.
}

Answer 3

You can capture the digits using groups

"[12]],23,asd".match(/\[\[(\d+)\]\]/)[1]
=> "12"

Answer 4

这是您可以使用的正则表达式，捕获组分别获得$1和$2 ，分别为 12 和 43

\[\[(\d+)\]\]\S+\[\[(\d+)\]\]

Answer 5

If you need to get 12 you can just use what you mentioned with a capturing group \\[\\[(\\d+)\\]\\]

var myRegexp= /\[\[(\d+)\]\]/;
var myString='[[12]],23,asd';
var match = myRegexp.exec(myString);
console.log(match[1]); // will have 12

Answer 6

I've only done it with 2 regExps, haven't found the way to do it with one:

var matches = '[[12]],23,asd'.match(/\[{2}(\d+)\]{2}/ig),
    intStr = matches[0].match(/\d+/ig);

console.log(intStr);