Call to Member function on Array

Question

So I'm utilizing a for each to try to generate a menu dynamically from a MySQL database. Because there's more than one it will always return an array. I use multiple files to generate the menu. I use a class to create the menu

class menu extends db{
       public function LoadMainMenu() {
       global $db;
       $query = <<<SQL
       SELECT id,name
       FROM menu
       WHERE enabled = :active
       AND location = :mainmenu
SQL;
       $resource = $db->sitedb->prepare( $query );
       $resource->execute( array(
       ':active'    => '1',
       ':mainmenu'  => '1',
));
foreach($resource as $row){
       echo '<li><a href="viewPage?pageid='.$row['id'].'">'.$row['name'].'</a></li>';
   }
}
$menu = new menu();

My next file is my base.class.php file

function LoadMainMenu() {
global $menu;
$menu->LoadMainMenu();
}

Then I have my index.php file within my theme settings where I have it called

<ul class='topmenu'>
<?php LoadMainMenu(); ?>
</ul>

It then gives me the error that it's a call to a member function on an array on base.class.php; If anymore code would help please let me know.

Answer 1

Not Really an end all cure all, but it works. I added it within the db.class.php and then just added global $db and then called $db->GetMainMenu() within the main index.php Template and it seems to have worked. Other than that I'm not sure what else to do.