I'm trying to write a function that will reinterpret a set of bytes as a float
. I have viewed a Stackoverflow question which lead me to try reinterpret_cast<>()
on an array of characters, and I started experimenting with splitting a float into chars and then reassembling it again, but that only gives me seemingly random numbers rather than what I think the value should be, as the output is different each time. A few different examples are:
1.58661e-038
3.63242e-038
2.53418e-038
The float variable should contain the value 5.2.
Compiling the code:
float f = 5.2;
unsigned char* bytes = reinterpret_cast<unsigned char*>(&f);
float f1 = reinterpret_cast<float&>(bytes);
std::cout << f1 << std::endl;
gave me
1.75384e-038
And then of course, a different number each time the program is run. Interestingly, however, if I put the code in a loop and execute it several times in a single run, the output stays consistent. This leads me to think it might be a memory location, but if so, I'm not sure how to access the real value of the variable - the dereference operator doesn't work, because it's not a pointer.
So my question is - How can I split a variable of type float
(and later on, a double
) into individual bytes (allowing me to modify the bits), and then reassemble it.
Any help would be greatly appreciated.
bytes
is a pointer .
Change
float f1 = reinterpret_cast<float&>(bytes);
to
float f1 = *reinterpret_cast<float*>(bytes);
// Cast to a different pointer... ^
// ^ ...and dereference that pointer.
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