How to convert datetime.strptime() weird date format ( with the word “of” in it)?

Question

当我得到这种日期格式时，是否可以将字符串转换为datetime对象：

9th of April 2015 03:00

Answer 1

You can also let dateutil do the job:

>>> from dateutil.parser import parse
>>> s = "9th of April 2015 03:00"
>>> parse(s)
datetime.datetime(2015, 4, 9, 3, 0)

Answer 2

Alternatively:

t = '9th of April 2015 03:00'
prefix = t.split()[0][-2:]
datetime.datetime.strptime(t, '%d{0} of %B %Y %H:%M'.format(prefix))

datetime.datetime(2015, 4, 9, 3, 0)

Updated: However I believe @alecxe's answer is the best among for general use case.

Answer 3

Yes, you just need to specify a correct position and type for your datetime objects!

>>> datetime.datetime.strptime('9th of April 2015 03:00','%dth of %B %Y %H:%M')
datetime.datetime(2015, 4, 9, 3, 0)

Note that as mentioned in comment you can't use of this recipe for other strings that contain other numbers of day like 1st and 2nd , so as a more general way as @alecxe mentioned you can use dateutil.parser.parse