I want to remove all li
except first child This code is removing all li
..
function clearAll() {
var sidemenu = document.getElementById('side_menu');
while (sidemenu.childNodes.length > 1) {
sidemenu.removeChild(sidemenu.lastChild);
}
}
Any suggestion?
use sidemenu.children
instead of sidemenu.childNodes
sidemenu.children
will return only the elements which are under the given node.
sidemenu.childNodes
will return both elements as well as text nodes, which is not the list of items you require. If you check the value returned by lastChild
it would be an empty text node and not an li
. That is why all the li
were getting removed.
function clearAll() {
var sidemenu = document.getElementById('side_menu');
while (sidemenu.children.length > 1) {
sidemenu.removeChild(sidemenu.lastChild);
}
}
Try doing:
while (sidemenu.childNodes.length > 2) {
//...
}
(Change the condition in the while loop.)
sidemenu.childNodes
actually has one extra text field. For that reason we need to increment the number in the condition of while loop.
jsFiddle Demo (checkout the console)
That ways, all of your <li>
's except the first one will be removed.
To keep the first child change
sidemenu.childNodes.length > 1
to
sidemenu.childNodes.length > 2
function clearAll() {
var sidemenu = document.getElementById('side_menu');
while (sidemenu.childNodes.length > 2) {
sidemenu.removeChild(sidemenu.lastChild);
}
}
如果您使用jQuery,则可以执行以下操作:
$('#side_menu li:not(:first)').remove();
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