javascript string: remove all except numbers and the first “.”

Question

For example:

"10.0.cm" goes to "10.0"

and

"10.0.m" goes to "10.0"

and

"3" stays as "3"

etc...

I tried this:

values[3].replace(/[^0-9.,]+/, '')

but this still leaves the "." after the number, eg: 10.0.

Thanks for your help...

Answer 1

 var values = ["10.0.cm", "10.0.m", "3"]; var patten = /\\d+(\\.\\d+)?/g; for (var i = 0; i < values.length; i++) { console.info(values[i].match(patten)); } 

Answer 2

下面的正则表达式应该解决它

values[3].replace(/\.+[a-z]*$/, '')

Answer 3

The problem you've described isn't a simple "find numbers in a String "

It's not easy to do this in one step because RegExp in JavaScript doesn't support lookbacks. However

• It's pretty easy to remove all characters which aren't a digit or .
• It's pretty easy to find specific chars in a String
• It's pretty easy to build a String

var str = 'foo_1.0.bar.1.2.xyz';

str = str.replace(/[^\d\.]/g, '').split('.');
str = str[0] ? str[0] + '.' + str.slice(1).join('') : '';

str; // "1.012"