I would like to reverse an array of string in Objective-C.
I know there is a in built-method of doing it as follows:
NSArray* reversedArray = [[inputString reverseObjectEnumerator] allObjects];
but I want to implement same functionality with coding as follows and getting the following error.
#import <Foundation/Foundation.h>
int main(int argc, const char * argv[]) {
@autoreleasepool {
NSMutableArray *inputString = [NSMutableArray arrayWithObjects:@"a", @"b", @"c", @"d", @"e", @"f", @"g", @"h", @"i", nil];
int lenArray= (int)[inputString count];
NSMutableArray *reverseString=[[NSMutableArray alloc]initWithCapacity:lenArray];
for(int i=lenArray-1;i>0;i--)
{
[reverseString insertObject:inputString[i] atIndex:i];
}
return 0;
}
}
Terminating app due to uncaught exception 'NSRangeException', reason: ' -[__NSArrayM insertObject:atIndex:]: index 8 beyond bounds for empty array'
[reverseString insertObject:inputString[i] atIndex:i];
is the problem - specifically the atIndex:i
part. You've created your mutable array with a large enough capacity, however it is still empty so specifying the index here is not what you meant to do.
Instead, just use addObject: [reverseString addObject:inputString[i]];
Try this:
for (int i = lenArray-1; i >= 0; i--) {
[reverseString addObject:inputString[i]];
}
Note: Just use addObject:
and change your for-loop condition to i >= 0
, otherwise the "a" will be missing.
Enjoy!
Here is the complete solution:
#import <Foundation/Foundation.h>
int main(int argc, const char * argv[]) {
@autoreleasepool {
NSMutableArray *inputString = [NSMutableArray arrayWithObjects:@"a", @"b", @"c", @"d", @"e", @"f", @"g", @"h", @"i", nil];
// NSArray* reversedArray = [[inputString reverseObjectEnumerator] allObjects];
int lenArray= (int)[inputString count];
NSMutableArray *reverseString=[[NSMutableArray alloc]initWithCapacity:lenArray];
for (int i = lenArray-1; i >= 0; i--) {
[reverseString addObject:inputString[i]];
}
for(int i=0;i<=lenArray-1;i++)
{
NSLog(@"%@\n", [reverseString objectAtIndex:i]);
}
return 0;
}
}
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