$sql = "SELECT s1.roomtype, s1.roomno, s1.checkin,s1.checkout FROM
guestrocordtransac s1
JOIN guestrocord s2
ON s1.roomtype = s2.roomtype AND s1.roomno != s2.roomno
WHERE s1.checkin = '".$date1."' BETWEEN s2.checkin = '".$date1."' AND s2.checkout='".$date2."' ";
I dont know where it went wrong .. i have to check roomtype,room no , on and between checkin and checkout date...
Iam getting the roomttype,roomno ,checkin,checkout values from the form ..Now i have to compare it with database.
Here
$sql = "SELECT s1.roomtype, s1.roomno, s1.checkin,s1.checkout FROM
guestrocordtransac s1
JOIN guestrocord s2
ON s1.roomtype = s2.roomtype AND s1.roomno != s2.roomno
WHERE s1.checkin = '".$date1."' BETWEEN s2.checkin = '".$date1."' AND s2.checkout='".$date2."' ";
you are having an invalid syntax in your where
clause, as you should not check equality in the between
operands. This should fix the issue:
$sql = "SELECT s1.roomtype, s1.roomno, s1.checkin,s1.checkout FROM
guestrocordtransac s1
JOIN guestrocord s2
ON s1.roomtype = s2.roomtype AND s1.roomno != s2.roomno
WHERE s1.checkin = '".$date1."' BETWEEN '".$date1."' AND '".$date2."' ";
Read more about between
here .
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