I have the follow json.
{
foo:{
id:1
},
name:'Albert',
age: 32
}
How can I deserialize to Java Pojo
public class User {
private int fooId;
private String name;
private int age;
}
You can do one of the following:
Create a concrete type representing Foo
:
public class Foo { private int id; ... }
Then in User
you would have:
public class User { private Foo foo; ... }
Use a Map<String, Integer>
:
public class User { private Map<String, Integer> foo; ... }
If other callers are really expecting you to have a getFooId
and a setFooId
, you can still provide these methods and then either delegate to Foo
or the Map
depending on the option you choose. Just make sure that you annotate these with @JsonIgnore
since they aren't real properties.
This is what you need to deserialize, using the JsonProperty
annotations in your constructor.
import com.fasterxml.jackson.annotation.JsonProperty;
import com.fasterxml.jackson.databind.JsonNode;
import com.fasterxml.jackson.databind.ObjectMapper;
import java.io.IOException;
public class User {
private int fooId;
private String name;
private int age;
public int getFooId() {
return fooId;
}
public String getName() {
return name;
}
public int getAge() {
return age;
}
public User(@JsonProperty("age") Integer age, @JsonProperty("name") String name,
@JsonProperty("foo") JsonNode foo) {
this.age = age;
this.name = name;
this.fooId = foo.path("id").asInt();
}
public static void main(String[] args) {
ObjectMapper objectMapper = new ObjectMapper();
String json = "{\"foo\":{\"id\":1}, \"name\":\"Albert\", \"age\": 32}" ;
try {
User user = objectMapper.readValue(json, User.class);
System.out.print("User fooId: " + user.getFooId());
} catch (IOException e) {
e.printStackTrace();
}
}
}
Output:
User fooId: 1
Hope it helps,
Jose Luis
You can use a very helpful gson google API.
First of all, create these two classes:
User class:
public class User{
Foo foo;
String name;
int age;
//getters and setters
}
Foo class:
public class Foo{
int id;
//getters and setters
}
If you have a example.json
file then deserialize it as follow
Gson gson = new Gson();
User data = gson.fromJson(new BufferedReader(new FileReader(
"example.json")), new TypeToken<User>() {
}.getType());
If you have a exampleJson
String then deserialize it as follow
Gson gson = new Gson();
User data = gson.fromJson(exampleJson, User.class);
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