I've been trying to implement a function where given with two arrays,
array1 's elements is used as conditions to filter out elements in array2 .
For instance:
array1= [apple, grapes, oranges]
array2= [potato, pears, grapes, berries, apples, oranges]
After feeding into a function, array2 should have elements as such:
filter_twoArrays(array1,array2)
array2= [grapes, apples, oranges]
I've tried the following code, using for loops and array.splice(), but the problem I am seeing is that when I use the splice method, it seems that it changes the lengths of array2 in the for loop:
function filter_twoArrays(filter,result){
for(i=0; i< filter.length; i++){
for(j=0; j< result.length; j++){
if(filter[i] !== result[j]){
result.splice(j,1)
}
}
}
Any inputs will be greatly appreciated on how to refine the filter function
cheers!
You can use filter as follow
var array1 = ['apples', 'grapes', 'oranges', 'banana'], array2 = ['potato', 'pears', 'grapes', 'berries', 'apples', 'oranges']; var intersection = array1.filter(function(e) { return array2.indexOf(e) > -1; }); console.log(intersection);
You can also add this method on Array prototype and call it directly on array
Array.prototype.intersection = function(arr) { return this.filter(function(e) { return arr.indexOf(e) > -1; }); }; var array1 = ['apples', 'grapes', 'oranges', 'banana'], array2 = ['potato', 'pears', 'grapes', 'berries', 'apples', 'oranges']; var intersection = array1.intersection(array2); console.log(intersection);
Hi this is a porting of the function array_intersect php. Should be good for you http://phpjs.org/functions/array_intersect/
function array_intersect(arr1) {
// discuss at: http://phpjs.org/functions/array_intersect/
// original by: Brett Zamir (http://brett-zamir.me)
// note: These only output associative arrays (would need to be
// note: all numeric and counting from zero to be numeric)
// example 1: $array1 = {'a' : 'green', 0:'red', 1: 'blue'};
// example 1: $array2 = {'b' : 'green', 0:'yellow', 1:'red'};
// example 1: $array3 = ['green', 'red'];
// example 1: $result = array_intersect($array1, $array2, $array3);
// returns 1: {0: 'red', a: 'green'}
var retArr = {},
argl = arguments.length,
arglm1 = argl - 1,
k1 = '',
arr = {},
i = 0,
k = '';
arr1keys: for (k1 in arr1) {
arrs: for (i = 1; i < argl; i++) {
arr = arguments[i];
for (k in arr) {
if (arr[k] === arr1[k1]) {
if (i === arglm1) {
retArr[k1] = arr1[k1];
}
// If the innermost loop always leads at least once to an equal value, continue the loop until done
continue arrs;
}
}
// If it reaches here, it wasn't found in at least one array, so try next value
continue arr1keys;
}
}
return retArr;
}
You can use some
, like this:
let newArray = array2.filter(
(array22) => !array1.some((array11) => array11.id === array22._id));
Since you have tagged javascript here is the solution.
function f1(x, y) {
var t = y.slice(0);
var r = [];
for (var i = 0; i < x.length; i++) {
for (var j = 0; j < y.length; j++) {
if (x[i] === y[j]) {
[].push.apply(r, t.splice(j, 1));
}
}
}
console.log(r)
y.length = 0;
[].push.apply(y, r);
}
Here is one simple way based on your code
function array_filter(filter, result) {
var filterLen = filter.length;
var resultLen = result.length;
for (i = 0; i < resultLen; i++) {
for (j = 0; j < filterLen; j++) {
if (!contains(filter, result[i]))
result.splice(i, 1);
}
}
}
//Return boolean depending if array 'a' contains item 'obj'
function contains(array, value) {
for (var i = 0; i < array.length; i++) {
if (array[i] == value) {
return true;
}
}
return false;
}
Mark the items which are to be filtered out via delete result[index]
manipulate them as needed.
JavaScript
window.onload = runs;
function runs() {
var array1 = ["apples", "grapes", "oranges"];
var array2 = ["potato", "pears", "grapes", "berries", "apples", "oranges"];
var result = filter_twoArrays(array1, array2);
function filter_twoArrays(filter, result) {
var i = 0,
j = 0;
for (i = 0; i < result.length; i++) {
var FLAG = 0;
for (j = 0; j < filter.length; j++) {
if (filter[j] == result[i]) {
FLAG = 1;
}
}
if (FLAG == 0) delete result[i];
}
return result;
}
var body = document.getElementsByTagName("body")[0];
var i = 0;
for (i = 0; i < result.length; i++) {
if (result[i] !== undefined)
body.innerHTML = body.innerHTML + result[i] + " ";
}
}
You can use
const arr1 = [1, 2, 3];
const arr2 = [2, 3];
arr1.filter(e => arr2.indexOf(e) > -1 ? false : true); // [1]
Came here some week back to find a solution to a problem like this but its a pity I couldn't get what I wanted, but now I figured it out in a more simple way. using the arrow function, .filter() method and .includes() method.
Declare an arrow function that takes in two arguments:
const filterTwoArrays = (string1, string2) => string1.filter(item => string2.includes(item));
console.log(filterTwoArrays(array1, array2)).
const func = array1.filter(item => array2.includes(item));
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