Converting an output from Hexadecimal to Decimal in c++

Question

I was trying to find the memory address of an array elements but the output is turning out to be in Hexadecimal. I would appreciate if u could tell me how to convert it to a Decimal output.

Here is the Code,

#include<iostream>
using namespace std;

 int main()
  {
   int a[4];

   cout << "Address of a[0] = " << &a << endl;
   cout << "Address of a[1] = " << &a[1] << endl;
   cout << "Address of a[2] = " << &a[2] << endl;
   cout << "Address of a[3] = " << &a[3] << endl;

   cin.get();

   return 0;
  }

Answer 1

In C++11 you can cast to uintptr_t , like

cout << "Address of a[0] = " << static_cast<uintptr_t>(&a) << endl;

The type uintptr_t is specifically designed to represent any possible pointer, so the solution is portable.

I am not aware of a portable solution in C++98/03, although a cast to size_t often (but not always) works. Related: Converting a pointer into an integer .

---

EDIT

Looking at http://en.cppreference.com/w/cpp/types/integer and also at the C++ standard 18.4.1 Header <cstdint> synopsis [cstdint.syn] , it looks like uintptr_t is optional . I have no idea whether there is an implementation that does not define it, and why would one chose to not define it. Any comments are welcome.