#include <string>
#include <iostream>
using namespace std;
const string hexConversion = "0123456789ABCDEF";
int main() {
int dec, remainder, quotient;
string hexNum = "";
//input sequence
cout << "Enter a decimal number: ";
cin >> dec;
quotient = dec;
//conversion
do {
remainder = quotient % 16;
quotient /= 16;
hexNum.insert(0, hexConversion[remainder]);
} while (quotient != 0);
cout << "Your number in hex is " << hexNum << ".";
}
I do not have a ton of experience coding, and would appreciate some insight as to what I'm doing wrong with this program! Here is the error being conveyed: invalid conversion from 'char' to 'const char*' [-fpermissive]
You are trying to use one of overloads of std::string::insert but none of them accept int and char:
One of the matching your needs is accepting position, count and symbol, so call hexNum.insert(0, 1, hexConverstion[remainder]);
If you were thinking of using the following function:
iterator insert( iterator pos, CharT ch );
you need to use:
hexNum.insert(hexNum.begin(), hexConverstion[remainder]);
That error is coming because there is no such overloaded version of string::insert
which takes int
and char
as arguments.
You can use this overloaded version:
string& insert (size_t pos, size_t n, char c);
where n = 1
in your case, as you want to add a character once only.
, or
iterator insert (iterator p, char c);
where p = hexNum.begin()
Checkout http://www.cplusplus.com/reference/string/string/insert/
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