Python http get - cannot replicate a curl request with headers
Question
I have the following curl command:
curl -H "User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64; rv:38.0) Gecko/20100101 Firefox/38.0" -H "Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8" -H "Connection: keep-alive" -X GET http://example.com/en/number/111555000
Unfortunately I was not able to replicate it... I tried with:
url = http://example.com/en/number/111555000
headers = {'User-Agent':'Mozilla/5.0 (Windows NT 6.1; WOW64; rv:38.0) Gecko/20100101 Firefox/38.0', 'Accept':'text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8', 'Connection':'keep-alive',}
req = urllib2.Request(url, None, headers)
resp = urllib2.urlopen(req)
print resp.read()
but the server recognized some how that the request is "fake" and forwards me to google (reply from server is: HTTP/1.1 301 Moved Permanently ). With curl instead I receive the original page.
Any ideas or suggestions? Thank you dk
EDIT: some additional infos:
$ nc example.com 80
GET /en/number/111555000 HTTP/1.1
Host: example.com
HTTP/1.1 301 Moved Permanently
Date: Fri, 29 May 2015 18:51:05 GMT
Server: Apache
X-Powered-By: PHP/5.5.24
Location: http://www.google.de
Content-Length: 0
Content-Type: text/html
$ nc example.com 80
GET /en/number/111555000 HTTP/1.1
Host: example.com
User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64; rv:38.0) Gecko/20100101 Firefox/38.0
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8
Connection: keep-alive
HTTP/1.1 200 OK
Date: Fri, 29 May 2015 18:57:56 GMT
Server: Apache
X-Powered-By: PHP/5.5.24
Set-Cookie: session=a%3A4%3A%7Bs...
Set-Cookie: session=a%3A4%3A%7Bs...
Keep-Alive: timeout=2, max=200
Connection: Keep-Alive
Transfer-Encoding: chunked
Content-Type: text/html; charset=UTF-8
1c6f8
<!DOCTYPE html>
[...]
with curl:
$curl -X GET http://example.com/en/number/111555000
$
$ curl -H "User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64; rv:38.0) Gecko/20100101 Firefox/38.0" -H "Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8" -H "Connection: keep-alive" -X GET http://example.com/en/number/111555000
<!DOCTYPE html>
[...]
1 answers
solution1
2 ACCPTED 2015-05-29 19:02:33
I can get it to work with the requests library. Which is probably better to use.
import requests
url = "http://example.com/en/number/111555000"
headers = {'User-Agent':'Mozilla/5.0 (Windows NT 6.1; WOW64; rv:38.0) Gecko/20100101 Firefox/38.0', 'Accept':'text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8', 'Connection':'keep-alive',}
req = requests.get(url, headers=headers)
req.text
here is the requests library documentation
Hope it helps.
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