passing an array of structs to a function and changing it through the fucntion

Question

so this is my code but it wont compile for some reason.

Error 3 error C2036: 'pjs *' : unknown size Error 4 error C2100: illegal indirection
Error 5 error C2037: left of 'size' specifies undefined struct/union 'pjs'

void initArray(struct pjs* array)
{

    (*array[1]).size = 1;
}
struct pjs{
 char* name;
 int size;
 int price;
};
int main(int argc , char** argv)
{
    struct pjs array[10];
    initArray(array);
    system("PAUSE");
    return (0);
}

Answer 1

那简直应该是

array[1].size = 1;

Answer 2

Following may help:

struct pjs{
    char* name;
    int size;
    int price;
};

// safer to use one of the following declaration
// void initArray(pjs *array, std::size_t size) // simpler
// void initArray(pjs (&array)[10]) // more restrictive but unintuitive syntax
void initArray(pjs* array)
{
    array[1].size = 1;
}

int main()
{
    pjs array[10];
    initArray(array);
}

• Definition of pjs should be given before to use it (or requiring its size).
• array[1] is a pjs so *array[1] is illegal (as pjs no have operator* )

Answer 3

Correct your 1st statement of initArray to :

array[1].size = 1;

and cut paste the struct declaration to before the function.

Answer 4

If you want to initialize the entire array, you need to pass the array and a size to initArray .

int main(int argc , char** argv)
{
    struct pjs array[10];
    initArray(array, sizeof(array)/sizeof(array[0]));
    system("PAUSE");
    return (0);
}

and then, initialize each object the array as:

void initArray(struct pjs* array, size_t size)
{
   for (size_t i = 0; i < size; ++i )
   {
      array[i].size = 1;
      array[i].price = 0; // Or whatever makes sense
      array[i].name = malloc(1); // Or whatever makes sense. 
   }
}