Split a string only by first space in python

Question

I have string for example: "238 NEO Sports" . I want to split this string only at the first space. The output should be ["238","NEO Sports"] .

One way I could think of is by using split() and finally merging the last two strings returned. Is there a better way?

Answer 1

Just pass the count as second parameter to str.split function.

>>> s = "238 NEO Sports"
>>> s.split(" ", 1)
['238', 'NEO Sports']

Answer 2

RTFM:str.split(sep=None, maxsplit=-1)

>>> "238 NEO Sports".split(None, 1)
['238', 'NEO Sports']

Answer 3

Use string.split()

string = "238 NEO Sports"
print string.split(' ', 1)

Output:

['238', 'NEO Sports']

Answer 4

**Use in-built terminology, as it will helpful to remember for future reference. When in doubt always prefer string.split( shift+tab )

string.split(maxsplit = 1)