Serialize XML into CSharp class

Question

I have a xml string in a json data field. I want to extract that value and compare that to the database's value for that field.

I used xsd.exe to generate the class for that xml (saw from here ). I am using that class to deserialize the xml response. Then i used the method from here to deserialize.

I used

`XmlSerializer serializer1 = new XmlSerializer(typeof(class_gen_from_xml))

In the below code, I extracted the xml source from the json response and then did as below:

string xmlSource = "<ResultSet><Result precision=\"address\">    <Latitude>47.643727</Latitude></Result></ResultSet>";

XmlSerializer serializer = new XmlSerializer(typeof(ResultSet));
ResultSet output;

using (StringReader reader = new StringReader(xmlSource))
{
   output = (ResultSet)serializer.Deserialize(reader);
}

` And I am getting an Exception and debugging reveals nothing at all. Is there something I am missing in the code ?

Answer 1

Probably something wrong with your ResultSet class, this works fine for me:

[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
[System.Xml.Serialization.XmlRootAttribute(Namespace = "", IsNullable = false)]
public partial class ResultSet
{
    private ResultSetResult[] resultField;

    [System.Xml.Serialization.XmlElementAttribute("Result")]
    public ResultSetResult[] Result
    {
        get
        {
            return this.resultField;
        }
        set
        {
            this.resultField = value;
        }
   }
}

[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
public partial class ResultSetResult
{
    private decimal latitudeField;
    private string precisionField;

    public decimal Latitude
    {
        get
        {
            return this.latitudeField;
        }
        set
        {
           this.latitudeField = value;
        }
    }

    [System.Xml.Serialization.XmlAttributeAttribute()]
    public string precision
    {
        get
        {
            return this.precisionField;
        }
        set
        {
            this.precisionField = value;
        }
    }
}

With your de-serialization code:

static void Main(string[] args)
{
    string xmlSource = "<ResultSet><Result precision=\"address\">    <Latitude>47.643727</Latitude></Result></ResultSet>";

    XmlSerializer serializer = new XmlSerializer(typeof(ResultSet));
    ResultSet output;

    using (StringReader reader = new StringReader(xmlSource))
    {
        output = (ResultSet)serializer.Deserialize(reader);
    }
}