Bash Scripting - AWK with Delimiter?

Question

I've got a header in a text file that looks like this:

First-Name:Last-Name:City:Home-Phone:Cell-Phone

What I need to do is display the Last-Name and the Cell-Phone number of each entry.

I'm new to bash scripting, and I'm not really sure what I can use to do this. I was told awk could be useful, but after looking around, I still don't quite understand how to use it.

Answer 1

用-F指定字段分隔符：

awk -F":" '{print $2, $5}'

Answer 2

I've found csvkit to be a useful utility for dealing with files like this. It's a lot more intuitive than the low-level unix utilities, though admittedly less powerful.

Take the following file:

First-Name:Last-Name:City:Home-Phone:Cell-Phone
Alice:Ashbury:Boston:111-111-1111:444-444-4444
Bob:Brown:Boston:222-222-2222:555-555-5555
Carol:Chaplin:Chicago:333-333-3333:666-666-6666

You can extract the second and fifth columns using csvcut :

csvcut test.csv -d ':' -c 2,5

Which gives the following output (including the header row):

Last-Name,Cell-Phone
Ashbury,444-444-4444
Brown,555-555-5555
Chaplin,666-666-6666

Combining the various csvkit commands together lets you quickly explore your data. For example, the following will filter to all lines with Boston as the City :

csvformat test.csv -d ':' | csvgrep -m Boston -c 3 | csvcut -c 2,5 | csvlook

And csvlook gives you pretty-printed output:

|------------+---------------|
|  Last-Name | Cell-Phone    |
|------------+---------------|
|  Ashbury   | 444-444-4444  |
|  Brown     | 555-555-5555  |
|------------+---------------|