Inheritance from either of two base classes using template specialization and constructor

Question

I am trying to inherit a "derived" class from either base1 or base2. I want to use template specialization for this purpose. I have the following

//base1
template<typename FT>
class base1
{
 public:
 base1(FT m)
 {}
};

//base2
template<typename FT>
class base2
{
  public:
  base2(FT m)
  {}
};

//define template specializations
template<int sType, typename FT>
class baseT {};

//for base1
template<typename FT>
class baseT<1,FT>
{
  public:
  typedef base1<FT> bType;
};

//for base2
template<typename FT>
class baseT<2,FT>
{
  public:
  typedef base2<FT> bType;
};

//Derived class which inherits either from base1 or base2
template<int sType, typename FT>
class derived : public baseT<sType,FT>::bType
{
  public:
  derived(FT m)
  {}
};

int main( )
{
  derived<1,float> a1(1);

  return 0;
}

This code is not compiling (on Linux platform) because the base class expects one argument but I am not sure how to pass it to the constructor of derived to make this work. (I dont want to use conditional). Any advice will help

Answer 1

//Derived class which inherits either from base1 or base2
template<int sType, typename FT>
class derived : public baseT<sType,FT>::bType
{
  public:
  derived(FT m) : baseT<sType,FT>::bType(m)
  {}
};

That's all you need to make it work. Initialize the base class.